API

C# Post time

1. • CommentAuthorRiaan
   • CommentTimeAug 2nd 2011

    
   I'm trying to log time against a current task, but get the error: "The remote server returned an error: (400) Bad Request."
   
   I'm an amateur c# developer and have come up following code:
   
   
   HttpWebRequest request = WebRequest.Create("https://api.myintervals.com/time/?taskid=1028237") as HttpWebRequest;
   request.Method = "POST";
   request.Accept = "application/xml";
   request.Headers.Add("Authorization", "Basic " + Convert.ToBase64String(System.Text.Encoding.ASCII.GetBytes("XXXXXX:")));
   StreamWriter writer = new StreamWriter(request.GetRequestStream());
   writer.Write(@"<?xml version=""1.0"" encoding=""UTF-8""?>
   <time>
   <worktypeid>164205</worktypeid>
   <personid>56602</personid>
   <date>2011-08-02</date>
   <time>07:46:00</time>
   <billable>f</billable>
   </time>");
   writer.Flush();
   // Get response
   using (HttpWebResponse response = request.GetResponse() as HttpWebResponse)
   {
   // Get the response stream
   StreamReader reader = new StreamReader(response.GetResponseStream());
   
   // Console application output
   textBox1.Text = reader.ReadToEnd();
   }
   
   
   Any ideas? Or samples I can look at?
   
   Thanks,
   R
2. •  
     CommentAuthorjprado
   • CommentTimeAug 2nd 2011 edited @ 08/02/2011 11:45 am

    
   Take out ?taskid=1028237 from the request URL and add it in the xml instead:
   
   <taskid>1028237</taskid>
   
   Also make sure that worktypeid is the correct id for the worktype. This id can be retrieved by listing the worktypes for the project.
3. • CommentAuthorRiaan
   • CommentTimeAug 3rd 2011 edited @ 08/04/2011 12:00 am

    
   Thank you very much for the response. I tried your suggestion, but did not work. I made some changes to the xml, but I think the problem is with the way I set up the request?
   
   Should I use any encryption or format the xml in any specific way?
   Would you please send a C# sample of how the to do a "POST"?
   
   --my code--
   HttpWebRequest request = WebRequest.Create("https://api.myintervals.com/time/") as HttpWebRequest;
   request.Method = "POST";
   request.Accept = "application/xml";
   request.Headers.Add("Authorization", "Basic " + Convert.ToBase64String(System.Text.Encoding.ASCII.GetBytes("XXXXXXX:")));
   
   StreamWriter writer = new StreamWriter(request.GetRequestStream());
   writer.Write(@"<?xml version=""1.0"" encoding=""UTF-8""?>
   <time>
   <taskid>1028237</taskid>
   <worktypeid>164205</worktypeid>
   <personid>56602</personid>
   <date>2011-08-02</date>
   <time>1</time>
   <billable>f</billable>
   </time>");
   writer.Flush();
   
   // Get response
   using (HttpWebResponse response = request.GetResponse() as HttpWebResponse)
   {
   
   // Get the response stream
   StreamReader reader = new StreamReader(response.GetResponseStream());
   
   // Console application output
   
   textBox1.Text = reader.ReadToEnd();
   }
4. •  
     CommentAuthorjprado
   • CommentTimeAug 4th 2011

    
   Here is a C# sample:
   

   
   // Create a request using a URL that can receive a post. 
   HttpWebRequest request = (HttpWebRequest)WebRequest.Create("https://api.myintervals.com/time/");
   request.Accept = "application/xml";
   request.Headers.Add("Authorization", "Basic " + Convert.ToBase64String(Encoding.ASCII.GetBytes("xx:")));
   
   // Set the Method property of the request to POST.
   request.Method = "POST";
   // Create POST data and convert it to a byte array.
   string postData = @"<?xml version=""1.0"" encoding=""UTF-8""?>
   <time>
   <taskid>1028237</taskid>
   <worktypeid>164205</worktypeid>
   <personid>56602</personid>
   <date>2011-08-02</date>
   <time>10</time>
   <billable>t</billable>
   </time>";
   byte[] byteArray = Encoding.UTF8.GetBytes (postData);
   // Set the ContentType property of the WebRequest.
   request.ContentType = "application/xml";
   // Set the ContentLength property of the WebRequest.
   request.ContentLength = byteArray.Length;
   // Get the request stream.
   Stream dataStream = request.GetRequestStream ();
   // Write the data to the request stream.
   dataStream.Write (byteArray, 0, byteArray.Length);
   // Close the Stream object.
   dataStream.Close ();
   // Get the response.
   WebResponse response = request.GetResponse ();
   // Display the status.
   Console.WriteLine (((HttpWebResponse)response).StatusDescription);
   // Get the stream containing content returned by the server.
   dataStream = response.GetResponseStream ();
   // Open the stream using a StreamReader for easy access.
   StreamReader reader = new StreamReader (dataStream);
   // Read the content.
   string responseFromServer = reader.ReadToEnd ();
   // Display the content.
   Console.WriteLine (responseFromServer);
   // Clean up the streams.
   reader.Close ();
   dataStream.Close ();
   response.Close ();
   

5. • CommentAuthorRiaan
   • CommentTimeAug 5th 2011

    
   Thank you very much, this works perfectly!